[P0] Reduce all FUs to one out

[tancheng]

VectorCGRA/fu/flexible/FlexibleFuRTL.py

Lines 94 to 95 in 49a4018

	s.send_out[j].msg @= s.fu[i].send_out[j].msg
	s.send_out[j].en @= s.fu[i].send_out[j].en

instead of nested for loop.

[emrahuzucar355]

jobs:
build:
runs-on: ubuntu-20.04
steps:
- name: Check out code
uses: actions/checkout@v2
- name: Set up Python
uses: actions/setup-python@v4
with:
python-version: '3.8' # Python sürümünü burada belirtebilirsiniz
- name: Install Dependencies
run: |
sudo apt-get update
sudo apt-get install -y llvm-12

[tancheng]

Thanks @emrahuzucar355, runs-on: ubuntu-20.04 can walk around our version incompatible issue between python and ubuntu22 for now.

[tancheng]

The nested-for-loop can be replaced with a MUX by using en (val in the latest master) of each FU. However, note that the number of FUs would be changed/parameterized via PyMTL's parameterization system.