-
Notifications
You must be signed in to change notification settings - Fork 46
New issue
Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.
By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.
Already on GitHub? Sign in to your account
d3.append(node) is not working in d3.js, so needs to be changed to the function returning node #439
Labels
Comments
The difference is that I usually use code like this: var d3Selection = d3.select(...)...;
var anotherD3Selection = d3.select(...)...;
d3Selection.....append(anotherD3Selection.node()); but according to d3.js docs, it was wrong from the start (but so intuitive!) |
And so, relates to #405 |
For now, I'm changing it to: var ƒ = Rpd.unit;
d3.....append(ƒ(d3().....node())); But probably in some cases it would be convenient to use |
shamansir
added a commit
that referenced
this issue
Feb 17, 2017
….append(Rpd.unit(node)) everywhere, still some examples do fail
Merged
Fixed with #440 |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
I can't believe I used
d3_tiny
's.append(node)
ability every time, but by docs it seems it is exactly what actually happened.The text was updated successfully, but these errors were encountered: