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holiday.py
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from typing import Dict
import argparse
import requests
import datetime
DAY_OF_WEEK = {
"MONTAG": 0,
"DIENSTAG": 1,
"MITTWOCH": 2,
"DONNERSTAG": 3,
"FREITAG": 4,
"SAMSTAG": 5,
"SONNTAG": 6
}
INV_DOW = {v: k for k, v in DAY_OF_WEEK.items()}
STATES = ['bw', 'by', 'be', 'bb', 'hb', 'hh', 'he', 'mv',
'ni', 'nw', 'rp', 'sl', 'sn', 'st', 'sh', 'th']
URI_FT_SERVER = "https://get.api-feiertage.de"
def string_to_date(dt, d_format='%Y-%m-%d'):
return datetime.datetime.strptime(dt, d_format)
def date_to_string(date, d_format='%Y-%m-%d'):
return datetime.datetime.strftime(date, d_format)
def day_of_week(dt):
return string_to_date(dt).weekday()
def get_holiday(year: int, state: str = "by") -> Dict:
""" Get German holidays for given year and state.
:return: dict e.g. {'Neujahr': '2022-01-01', ...}
in case of Error raises RuntimeError
"""
result = requests.get(f"{URI_FT_SERVER}?years={year}&states={state}")
if not result.ok:
# it appears this WS is always returning ok, this code is probably never reached
raise RuntimeError("Web service error behaviour has changed")
content = result.json()
# error is inside content ...
if 'status' in content and content['status'] == 'error':
raise RuntimeError(content['error_description'])
# transform into a more suitable format
f_dict = {x['fname']: x['date'] for x in content['feiertage']}
return f_dict
if __name__ == '__main__':
parser = argparse.ArgumentParser()
parser.add_argument("-y", "--year", required=True, help="Jahr für das Brückentage ermittelt werden sollen.")
parser.add_argument("-s", "--state", required=True,
help=f"Bundesland zur Ermittlung der Urlaubstage. Kürzel={STATES}")
args = parser.parse_args()
assert args.state in STATES, f"Unbekanntes Bundesland: {args.state}; erwartet: {STATES}"
for h_name, h_date in get_holiday(args.year).items():
if day_of_week(h_date) == DAY_OF_WEEK['DIENSTAG']: # yesterday, i.e. delta=-1d
delta = datetime.timedelta(days=-1)
elif day_of_week(h_date) == DAY_OF_WEEK['DONNERSTAG']:
delta = datetime.timedelta(days=1) # tomorrow, i.e. delta=1d
else:
continue
b_day = date_to_string(string_to_date(h_date) + delta)
print(f'Brückentag zu {h_name} am {h_date} ist am {b_day}, ein {INV_DOW[day_of_week(b_day)]}.')