function pipe CFG (harmless redundancy)

[akashsridhar]

Remove intermediate redundant statement in func pipe CFG (it doesn't affect the correctness of the CFG. Just adds extra redundant statements - fix this)

example 1
m = (1,2) |> foo(3,4) |> bar

1 0 0 SEQ0
2 1 0 0 28 () ___e 0d1 0d2
3 1 1 0 28 .() ___d foo 0d3 0d4 ___e
4 1 2 0 28 .() ___c bar ___d
5 1 3 0 28 .() ___b ___c
6 1 4 0 28 .() ___a ___b
7 1 5 0 28 = m ___a

example 2
x = a |> foo

1 0 0 SEQ0
2 1 0 31 43 .() ___c a
3 1 1 31 43 .() ___b foo ___c
4 1 2 31 43 .() ___a ___b
5 1 3 31 43 = x ___a