JZZ.MIDI.Mtrk is not a constructor

[hr30]

I copied the code from the description of JZZ-midi-SMF into a file jzzTest.js:

const JZZ = require('jzz');
require ('jzz-midi-smf')(JZZ);
var smf = new JZZ.MIDI.SMF (0, 24),
    trk = new JZZ.MIDI.SMF.Mtrk (),
    chord = [60, 64, 67, 71];

smf.push (trk);
trk.smfBPM(120).ch(0) // subsequent calls will apply to channel 0
      .tick(96).noteOn('C6', 127).noteOn('Eb6', 127).noteOn('G6', 127)
      .tick(96).noteOff('C6').noteOff('Eb6').noteOff('G6')
      .tick(96).smfEndOfTrack();

when starting with node jzzTest.js I got the error Message:

 trk = new JZZ.MIDI.SMF.Mtrk (),
          ^

TypeError: JZZ.MIDI.SMF.Mtrk is not a constructor

I can't catch the fault.

[jazz-soft]

Please check your spelling: MTrk

[hr30]

Oops ... my fault.
Thanks.

[hr30]

Ok, I have corrected that fault.
Now the program ends without fault, but without sound.
I tried to put in front of that a snippet from another example in that way:

JZZ().or('Cannot start MIDI engine!')
    .openMidiOut().or('Cannot open MIDI Out port!')
    .trk. ...

but this ends allso in an error message:

    .trk.smfBPM(120).ch(0) // subsequent calls will apply to channel 0
        ^

TypeError: Cannot read properties of undefined (reading 'smfBPM')

Putting this in an .and-enclosure like .and (trk. ...) does not throw an error, but no sound occurs.
Wrapping this into a function like .and (function () {trk. ...) throws an error too.

Honestly said, I still have a lack of understanding this concept.

My aim was to use jzz-midi-smf in order to get an infinite sequential play of an array of notes or of random generated notes, and I don't know if this is the right way or how to realize this.

[jazz-soft]

trk is not a member of JZZ().openMidiOut().
I don't understand what you are trying to do.
You can send notes to MIDI Out without jzz-midi-smf.