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Added java and kotlin tasks 6, 7, 8, 9
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javadev committed Jan 22, 2024
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34 changes: 34 additions & 0 deletions src/main/java/g0001_0100/s0006_zigzag_conversion/Solution.java
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package g0001_0100.s0006_zigzag_conversion;

// #Medium #String

public class Solution {
public String convert(String s, int numRows) {
int sLen = s.length();
if (numRows == 1) {
return s;
}
int maxDist = numRows * 2 - 2;
StringBuilder buf = new StringBuilder();
for (int i = 0; i < numRows; i++) {
int index = i;
if (i == 0 || i == numRows - 1) {
while (index < sLen) {
buf.append(s.charAt(index));
index += maxDist;
}
} else {
while (index < sLen) {
buf.append(s.charAt(index));
index += maxDist - i * 2;
if (index >= sLen) {
break;
}
buf.append(s.charAt(index));
index += i * 2;
}
}
}
return buf.toString();
}
}
39 changes: 39 additions & 0 deletions src/main/java/g0001_0100/s0006_zigzag_conversion/readme.md
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6\. Zigzag Conversion

Medium

The string `"PAYPALISHIRING"` is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)

P A H N A P L S I I G Y I R

And then read line by line: `"PAHNAPLSIIGYIR"`

Write the code that will take a string and make this conversion given a number of rows:

string convert(string s, int numRows);

**Example 1:**

**Input:** s = "PAYPALISHIRING", numRows = 3

**Output:** "PAHNAPLSIIGYIR"

**Example 2:**

**Input:** s = "PAYPALISHIRING", numRows = 4

**Output:** "PINALSIGYAHRPI"

**Explanation:** P I N A L S I G Y A H R P I

**Example 3:**

**Input:** s = "A", numRows = 1

**Output:** "A"

**Constraints:**

* `1 <= s.length <= 1000`
* `s` consists of English letters (lower-case and upper-case), `','` and `'.'`.
* `1 <= numRows <= 1000`
17 changes: 17 additions & 0 deletions src/main/java/g0001_0100/s0007_reverse_integer/Solution.java
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package g0001_0100.s0007_reverse_integer;

// #Medium #Top_Interview_Questions #Math #Udemy_Integers

public class Solution {
public int reverse(int x) {
long rev = 0;
while (x != 0) {
rev = (rev * 10) + (x % 10);
x /= 10;
}
if (rev > Integer.MAX_VALUE || rev < Integer.MIN_VALUE) {
return 0;
}
return (int) rev;
}
}
35 changes: 35 additions & 0 deletions src/main/java/g0001_0100/s0007_reverse_integer/readme.md
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7\. Reverse Integer

Medium

Given a signed 32-bit integer `x`, return `x` _with its digits reversed_. If reversing `x` causes the value to go outside the signed 32-bit integer range <code>[-2<sup>31</sup>, 2<sup>31</sup> - 1]</code>, then return `0`.

**Assume the environment does not allow you to store 64-bit integers (signed or unsigned).**

**Example 1:**

**Input:** x = 123

**Output:** 321

**Example 2:**

**Input:** x = -123

**Output:** -321

**Example 3:**

**Input:** x = 120

**Output:** 21

**Example 4:**

**Input:** x = 0

**Output:** 0

**Constraints:**

* <code>-2<sup>31</sup> <= x <= 2<sup>31</sup> - 1</code>
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package g0001_0100.s0008_string_to_integer_atoi;

// #Medium #Top_Interview_Questions #String

public class Solution {
public int myAtoi(String str) {
if (str == null || str.length() == 0) {
return 0;
}
int i = 0;
boolean negetiveSign = false;
char[] input = str.toCharArray();
while (i < input.length && input[i] == ' ') {
i++;
}
if (i == input.length) {
return 0;
} else if (input[i] == '+') {
i++;
} else if (input[i] == '-') {
i++;
negetiveSign = true;
}
int num = 0;
while (i < input.length && input[i] <= '9' && input[i] >= '0') {
// current char
int tem = input[i] - '0';
tem = negetiveSign ? -tem : tem;
// avoid invalid number like 038
if (num == 0 && tem == '0') {
i++;
} else if (num == Integer.MIN_VALUE / 10 && tem <= -8 || num < Integer.MIN_VALUE / 10) {
return Integer.MIN_VALUE;
} else if (num == Integer.MAX_VALUE / 10 && tem >= 7 || num > Integer.MAX_VALUE / 10) {
return Integer.MAX_VALUE;
} else {
num = num * 10 + tem;
i++;
}
}
return num;
}
}
113 changes: 113 additions & 0 deletions src/main/java/g0001_0100/s0008_string_to_integer_atoi/readme.md
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8\. String to Integer (atoi)

Medium

Implement the `myAtoi(string s)` function, which converts a string to a 32-bit signed integer (similar to C/C++'s `atoi` function).

The algorithm for `myAtoi(string s)` is as follows:

1. Read in and ignore any leading whitespace.
2. Check if the next character (if not already at the end of the string) is `'-'` or `'+'`. Read this character in if it is either. This determines if the final result is negative or positive respectively. Assume the result is positive if neither is present.
3. Read in next the characters until the next non-digit character or the end of the input is reached. The rest of the string is ignored.
4. Convert these digits into an integer (i.e. `"123" -> 123`, `"0032" -> 32`). If no digits were read, then the integer is `0`. Change the sign as necessary (from step 2).
5. If the integer is out of the 32-bit signed integer range <code>[-2<sup>31</sup>, 2<sup>31</sup> - 1]</code>, then clamp the integer so that it remains in the range. Specifically, integers less than <code>-2<sup>31</sup></code> should be clamped to <code>-2<sup>31</sup></code>, and integers greater than <code>2<sup>31</sup> - 1</code> should be clamped to <code>2<sup>31</sup> - 1</code>.
6. Return the integer as the final result.

**Note:**

* Only the space character `' '` is considered a whitespace character.
* **Do not ignore** any characters other than the leading whitespace or the rest of the string after the digits.

**Example 1:**

**Input:** s = "42"

**Output:** 42

**Explanation:** The underlined characters are what is read in, the caret is the current reader position.

Step 1: "42" (no characters read because there is no leading whitespace)
^
Step 2: "42" (no characters read because there is neither a '-' nor '+')
^
Step 3: "42" ("42" is read in)
^

The parsed integer is 42. Since 42 is in the range [-2<sup>31</sup>, 2<sup>31</sup> - 1], the final result is 42.

**Example 2:**

**Input:** s = " -42"

**Output:** -42

**Explanation:**

Step 1: " -42" (leading whitespace is read and ignored)
^
Step 2: " -42" ('-' is read, so the result should be negative)
^
Step 3: " -42" ("42" is read in)
^
The parsed integer is -42.

Since -42 is in the range [-2<sup>31</sup>, 2<sup>31</sup> - 1], the final result is -42.

**Example 3:**

**Input:** s = "4193 with words"

**Output:** 4193

**Explanation:**

Step 1: "4193 with words" (no characters read because there is no leading whitespace)
^
Step 2: "4193 with words" (no characters read because there is neither a '-' nor '+')
^
Step 3: "4193 with words" ("4193" is read in; reading stops because the next character is a non-digit)
^
The parsed integer is 4193.

Since 4193 is in the range [-2<sup>31</sup>, 2<sup>31</sup> - 1], the final result is 4193.

**Example 4:**

**Input:** s = "words and 987"

**Output:** 0

**Explanation:**

Step 1: "words and 987" (no characters read because there is no leading whitespace)
^
Step 2: "words and 987" (no characters read because there is neither a '-' nor '+')
^
Step 3: "words and 987" (reading stops immediately because there is a non-digit 'w')
^
The parsed integer is 0 because no digits were read.

Since 0 is in the range [-2<sup>31</sup>, 2<sup>31</sup> - 1], the final result is 0.

**Example 5:**

**Input:** s = "-91283472332"

**Output:** -2147483648

**Explanation:**

Step 1: "-91283472332" (no characters read because there is no leading whitespace)
^
Step 2: "-91283472332" ('-' is read, so the result should be negative)
^
Step 3: "-91283472332" ("91283472332" is read in)
^
The parsed integer is -91283472332.

Since -91283472332 is less than the lower bound of the range [-2<sup>31</sup>, 2<sup>31</sup> - 1], the final result is clamped to -2<sup>31</sup> = -2147483648.

**Constraints:**

* `0 <= s.length <= 200`
* `s` consists of English letters (lower-case and upper-case), digits (`0-9`), `' '`, `'+'`, `'-'`, and `'.'`.
19 changes: 19 additions & 0 deletions src/main/java/g0001_0100/s0009_palindrome_number/Solution.java
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package g0001_0100.s0009_palindrome_number;

// #Easy #Math #Udemy_Integers

public class Solution {
public boolean isPalindrome(int x) {
if (x < 0) {
return false;
}
int rev = 0;
int localX = x;
while (localX > 0) {
rev *= 10;
rev += localX % 10;
localX /= 10;
}
return rev == x;
}
}
41 changes: 41 additions & 0 deletions src/main/java/g0001_0100/s0009_palindrome_number/readme.md
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9\. Palindrome Number

Easy

Given an integer `x`, return `true` if `x` is palindrome integer.

An integer is a **palindrome** when it reads the same backward as forward. For example, `121` is palindrome while `123` is not.

**Example 1:**

**Input:** x = 121

**Output:** true

**Example 2:**

**Input:** x = -121

**Output:** false

**Explanation:** From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.

**Example 3:**

**Input:** x = 10

**Output:** false

**Explanation:** Reads 01 from right to left. Therefore it is not a palindrome.

**Example 4:**

**Input:** x = -101

**Output:** false

**Constraints:**

* <code>-2<sup>31</sup> <= x <= 2<sup>31</sup> - 1</code>

**Follow up:** Could you solve it without converting the integer to a string?
2 changes: 1 addition & 1 deletion src/main/kotlin/g0001_0100/s0001_two_sum/Solution.kt
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package g0001_0100.s0001_two_sum;
package g0001_0100.s0001_two_sum

// #Easy #Top_100_Liked_Questions #Top_Interview_Questions #Array #Hash_Table
// #Data_Structure_I_Day_2_Array #Level_1_Day_13_Hashmap #Udemy_Arrays #Big_O_Time_O(n)_Space_O(n)
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package g0001_0100.s0002_add_two_numbers;
package g0001_0100.s0002_add_two_numbers

// #Medium #Top_100_Liked_Questions #Top_Interview_Questions #Math #Linked_List #Recursion
// #Data_Structure_II_Day_10_Linked_List #Programming_Skills_II_Day_15
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package g0001_0100.s0003_longest_substring_without_repeating_characters;
package g0001_0100.s0003_longest_substring_without_repeating_characters

// #Medium #Top_100_Liked_Questions #Top_Interview_Questions #String #Hash_Table #Sliding_Window
// #Algorithm_I_Day_6_Sliding_Window #Level_2_Day_14_Sliding_Window/Two_Pointer #Udemy_Strings
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package g0001_0100.s0004_median_of_two_sorted_arrays;
package g0001_0100.s0004_median_of_two_sorted_arrays

// #Hard #Top_100_Liked_Questions #Top_Interview_Questions #Array #Binary_Search #Divide_and_Conquer
// #Big_O_Time_O(log(min(N,M)))_Space_O(1)
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package g0001_0100.s0005_longest_palindromic_substring;
package g0001_0100.s0005_longest_palindromic_substring

// #Medium #Top_100_Liked_Questions #Top_Interview_Questions #String #Dynamic_Programming
// #Data_Structure_II_Day_9_String #Algorithm_II_Day_14_Dynamic_Programming
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