Skip to content

Latest commit

 

History

History
216 lines (211 loc) · 6.58 KB

147.md

File metadata and controls

216 lines (211 loc) · 6.58 KB

Results of GPT-4 on HumanEval/147

Date: 18 July, 2023
Model: gpt-4
Temperature: 0.2
Passing runs: 0
Total runs: 10
Success rate: 0%

Prompt

Tokens: 191

def get_max_triples(n):
    """
    You are given a positive integer n. You have to create an integer array a of length n.
        For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
        Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
    and a[i] + a[j] + a[k] is a multiple of 3.

    Example :
        Input: n = 5
        Output: 1
        Explanation: 
        a = [1, 3, 7, 13, 21]
        The only valid triple is (1, 7, 13).
    """

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

def get_max_triples(n):
    """
    You are given a positive integer n. You have to create an integer array a of length n.
        For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
        Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
    and a[i] + a[j] + a[k] is a multiple of 3.

    Example :
        Input: n = 5
        Output: 1
        Explanation: 
        a = [1, 3, 7, 13, 21]
        The only valid triple is (1, 7, 13).
    """A = [i*i - i + 1 for i in range(1,n+1)]
    ans = []
    for i in range(n):
        for j in range(i+1,n):
            for k in range(j+1,n):
                if (A[i]+A[j]+A[k])%3 == 0:
                    ans += [(A[i],A[j],A[k])]
    return len(ans)

Unit tests

def check(candidate):

    assert candidate(5) == 1
    assert candidate(6) == 4
    assert candidate(10) == 36
    assert candidate(100) == 53361

Runs

❌ Run 1

Start time: 2023-07-18 17:52:46
Duration: 31.58s
Completion tokens: 320
Result: Fail

def get_max_triples(n):
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = [0, 0, 0]
    for i in a:
        count[i % 3] += 1
    return count[0] * (count[0] - 1) * (count[0] - 2) // 6 + count[1] * count[2] * (count[2] - 1) // 2 + count[2] * count[1] * (count[1] - 1) // 2

❌ Run 2

Start time: 2023-07-18 17:52:29
Duration: 17.11s
Completion tokens: 234
Result: Fail

def get_max_triples(n):
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = [0, 0, 0]
    for i in a:
        count[i % 3] += 1
    return count[0] * (count[0] - 1) * (count[0] - 2) // 6 + count[1] * count[2] * (count[2] - 1) // 2 + count[2] * count[1] * (count[1] - 1) // 2

❌ Run 3

Start time: 2023-07-18 17:52:04
Duration: 24.51s
Completion tokens: 277
Result: Fail

def get_max_triples(n):
    a = [i*i - i + 1 for i in range(1, n+1)]
    count = [0, 0, 0]
    for i in a:
        count[i % 3] += 1
    return count[0]*(count[0]-1)*(count[0]-2)//6 + count[1]*count[2]*(count[2]-1)//2 + count[2]*count[1]*(count[1]-1)//2

❌ Run 4

Start time: 2023-07-18 17:51:54
Duration: 9.9s
Completion tokens: 139
Result: Fail

def get_max_triples(n):
    a = [i * i - i + 1 for i in range(1, n+1)]
    count = [0, 0, 0]
    for i in a:
        count[i % 3] += 1
    return count[0] * (count[0] - 1) * (count[0] - 2) // 6 + count[1] * count[2] * (count[2] - 1) // 2 + count[2] * count[1] * (count[1] - 1) // 2

❌ Run 5

Start time: 2023-07-18 17:51:31
Duration: 23.25s
Completion tokens: 291
Result: Fail

def get_max_triples(n):
    """
    You are given a positive integer n. You have to create an integer array a of length n.
        For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
        Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
    and a[i] + a[j] + a[k] is a multiple of 3.

    Example :
        Input: n = 5
        Output: 1
        Explanation: 
        a = [1, 3, 7, 13, 21]
        The only valid triple is (1, 7, 13).
    """
    a = [i * i - i + 1 for i in range(1, n+1)]
    count = [0, 0, 0]
    for i in a:
        count[i % 3] += 1
    return count[0] * (count[0] - 1) * (count[0] - 2) // 6 + count[1] * count[2] * (count[2] - 1) // 2 + count[1] * (count[1] - 1) * count[2] // 2

❌ Run 6

Start time: 2023-07-18 17:51:06
Duration: 25.33s
Completion tokens: 292
Result: Fail

def get_max_triples(n):
    """
    You are given a positive integer n. You have to create an integer array a of length n.
        For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1.
        Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, 
    and a[i] + a[j] + a[k] is a multiple of 3.

    Example :
        Input: n = 5
        Output: 1
        Explanation: 
        a = [1, 3, 7, 13, 21]
        The only valid triple is (1, 7, 13).
    """
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = [0, 0, 0]
    for i in a:
        count[i % 3] += 1
    return count[0] * (count[0] - 1) * (count[0] - 2) // 6 + count[1] * count[2] * (count[2] - 1) // 2 + count[2] * count[1] * (count[1] - 1) // 2

❌ Run 7

Start time: 2023-07-18 17:50:44
Duration: 21.87s
Completion tokens: 297
Result: Fail

def get_max_triples(n):
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = [0, 0, 0]
    for i in a:
        count[i % 3] += 1
    return count[0] * (count[0] - 1) * (count[0] - 2) // 6 + count[1] * count[2] * (count[2] - 1) // 2 + count[2] * count[1] * (count[1] - 1) // 2

❌ Run 8

Start time: 2023-07-18 17:50:23
Duration: 20.98s
Completion tokens: 279
Result: Fail

def get_max_triples(n):
    a = [i * i - i + 1 for i in range(1, n + 1)]
    cnt = [0, 0, 0]
    for i in a:
        cnt[i % 3] += 1
    return cnt[0] * (cnt[0] - 1) * (cnt[0] - 2) // 6 + cnt[1] * cnt[2] * (cnt[2] - 1) // 2 + cnt[1] * (cnt[1] - 1) * cnt[2] // 2

❌ Run 9

Start time: 2023-07-18 17:50:01
Duration: 21.59s
Completion tokens: 284
Result: Fail

def get_max_triples(n):
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = [0, 0, 0]
    for i in a:
        count[i % 3] += 1
    return count[0] * (count[0] - 1) * (count[0] - 2) // 6 + count[1] * count[2] * (count[2] - 1) // 2 + count[2] * count[1] * (count[1] - 1) // 2

❌ Run 10

Start time: 2023-07-18 17:49:32
Duration: 28.84s
Completion tokens: 298
Result: Fail

def get_max_triples(n):
    a = [i * i - i + 1 for i in range(1, n + 1)]
    count = [0, 0, 0]
    for i in a:
        count[i % 3] += 1
    return count[0] * (count[0] - 1) * (count[0] - 2) // 6 + count[1] * count[2] * (count[2] - 1) // 2 + count[2] * count[1] * (count[1] - 1) // 2