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Results of GPT-3.5 on HumanEval/69

Date: 18 July, 2023
Model: gpt-3.5-turbo
Temperature: 0.2
Passing runs: 6
Total runs: 10
Success rate: 60%

Prompt

Tokens: 191

def search(lst):
    '''
    You are given a non-empty list of positive integers. Return the greatest integer that is greater than 
    zero, and has a frequency greater than or equal to the value of the integer itself. 
    The frequency of an integer is the number of times it appears in the list.
    If no such a value exist, return -1.
    Examples:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''

The above is an incomplete Python code fragment. Return the complete and correct code with no additional text.

Correct solution

def search(lst):
    '''
    You are given a non-empty list of positive integers. Return the greatest integer that is greater than 
    zero, and has a frequency greater than or equal to the value of the integer itself. 
    The frequency of an integer is the number of times it appears in the list.
    If no such a value exist, return -1.
    Examples:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''frq = [0] * (max(lst) + 1)
    for i in lst:
        frq[i] += 1;

    ans = -1
    for i in range(1, len(frq)):
        if frq[i] >= i:
            ans = i
    
    return ans

Unit tests

def check(candidate):

    # manually generated tests
    assert candidate([5, 5, 5, 5, 1]) == 1
    assert candidate([4, 1, 4, 1, 4, 4]) == 4
    assert candidate([3, 3]) == -1
    assert candidate([8, 8, 8, 8, 8, 8, 8, 8]) == 8
    assert candidate([2, 3, 3, 2, 2]) == 2

    # automatically generated tests
    assert candidate([2, 7, 8, 8, 4, 8, 7, 3, 9, 6, 5, 10, 4, 3, 6, 7, 1, 7, 4, 10, 8, 1]) == 1
    assert candidate([3, 2, 8, 2]) == 2
    assert candidate([6, 7, 1, 8, 8, 10, 5, 8, 5, 3, 10]) == 1
    assert candidate([8, 8, 3, 6, 5, 6, 4]) == -1
    assert candidate([6, 9, 6, 7, 1, 4, 7, 1, 8, 8, 9, 8, 10, 10, 8, 4, 10, 4, 10, 1, 2, 9, 5, 7, 9]) == 1
    assert candidate([1, 9, 10, 1, 3]) == 1
    assert candidate([6, 9, 7, 5, 8, 7, 5, 3, 7, 5, 10, 10, 3, 6, 10, 2, 8, 6, 5, 4, 9, 5, 3, 10]) == 5
    assert candidate([1]) == 1
    assert candidate([8, 8, 10, 6, 4, 3, 5, 8, 2, 4, 2, 8, 4, 6, 10, 4, 2, 1, 10, 2, 1, 1, 5]) == 4
    assert candidate([2, 10, 4, 8, 2, 10, 5, 1, 2, 9, 5, 5, 6, 3, 8, 6, 4, 10]) == 2
    assert candidate([1, 6, 10, 1, 6, 9, 10, 8, 6, 8, 7, 3]) == 1
    assert candidate([9, 2, 4, 1, 5, 1, 5, 2, 5, 7, 7, 7, 3, 10, 1, 5, 4, 2, 8, 4, 1, 9, 10, 7, 10, 2, 8, 10, 9, 4]) == 4
    assert candidate([2, 6, 4, 2, 8, 7, 5, 6, 4, 10, 4, 6, 3, 7, 8, 8, 3, 1, 4, 2, 2, 10, 7]) == 4
    assert candidate([9, 8, 6, 10, 2, 6, 10, 2, 7, 8, 10, 3, 8, 2, 6, 2, 3, 1]) == 2
    assert candidate([5, 5, 3, 9, 5, 6, 3, 2, 8, 5, 6, 10, 10, 6, 8, 4, 10, 7, 7, 10, 8]) == -1
    assert candidate([10]) == -1
    assert candidate([9, 7, 7, 2, 4, 7, 2, 10, 9, 7, 5, 7, 2]) == 2
    assert candidate([5, 4, 10, 2, 1, 1, 10, 3, 6, 1, 8]) == 1
    assert candidate([7, 9, 9, 9, 3, 4, 1, 5, 9, 1, 2, 1, 1, 10, 7, 5, 6, 7, 6, 7, 7, 6]) == 1
    assert candidate([3, 10, 10, 9, 2]) == -1

Runs

❌ Run 1

Start time: 2023-07-18 17:17:20
Duration: 3.09s
Completion tokens: 76
Result: Fail

def search(lst):
    freq_dict = {}
    for num in lst:
        if num in freq_dict:
            freq_dict[num] += 1
        else:
            freq_dict[num] = 1
    
    for num, freq in freq_dict.items():
        if freq >= num and num > 0:
            return num
    
    return -1

✅ Run 2

Start time: 2023-07-18 17:17:12
Duration: 7.49s
Completion tokens: 196
Result: Pass

def search(lst):
    '''
    You are given a non-empty list of positive integers. Return the greatest integer that is greater than 
    zero, and has a frequency greater than or equal to the value of the integer itself. 
    The frequency of an integer is the number of times it appears in the list.
    If no such a value exist, return -1.
    Examples:
        search([4, 1, 2, 2, 3, 1]) == 2
        search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
        search([5, 5, 4, 4, 4]) == -1
    '''
    max_num = -1
    for num in lst:
        if lst.count(num) >= num and num > max_num:
            max_num = num
    return max_num

✅ Run 3

Start time: 2023-07-18 17:17:08
Duration: 3.77s
Completion tokens: 91
Result: Pass

def search(lst):
    freq_dict = {}
    for num in lst:
        if num in freq_dict:
            freq_dict[num] += 1
        else:
            freq_dict[num] = 1
    
    max_num = -1
    for num, freq in freq_dict.items():
        if num > 0 and freq >= num:
            max_num = max(max_num, num)
    
    return max_num

❌ Run 4

Start time: 2023-07-18 17:17:05
Duration: 2.98s
Completion tokens: 71
Result: Fail

def search(lst):
    frequency = {}
    for num in lst:
        if num in frequency:
            frequency[num] += 1
        else:
            frequency[num] = 1
    
    for num in lst:
        if num > 0 and frequency[num] >= num:
            return num
    
    return -1

✅ Run 5

Start time: 2023-07-18 17:17:02
Duration: 3.17s
Completion tokens: 86
Result: Pass

def search(lst):
    freq_dict = {}
    for num in lst:
        if num in freq_dict:
            freq_dict[num] += 1
        else:
            freq_dict[num] = 1
    
    max_num = -1
    for num, freq in freq_dict.items():
        if freq >= num and num > max_num:
            max_num = num
    
    return max_num

❌ Run 6

Start time: 2023-07-18 17:16:58
Duration: 3.56s
Completion tokens: 77
Result: Fail

def search(lst):
    freq_dict = {}
    for num in lst:
        if num in freq_dict:
            freq_dict[num] += 1
        else:
            freq_dict[num] = 1
    
    for num, freq in freq_dict.items():
        if freq >= num and num > 0:
            return num
    
    return -1

✅ Run 7

Start time: 2023-07-18 17:16:55
Duration: 3.33s
Completion tokens: 81
Result: Pass

def search(lst):
    freq_dict = {}
    for num in lst:
        if num in freq_dict:
            freq_dict[num] += 1
        else:
            freq_dict[num] = 1
    
    max_num = -1
    for num, freq in freq_dict.items():
        if freq >= num and num > max_num:
            max_num = num
    
    return max_num

✅ Run 8

Start time: 2023-07-18 17:16:51
Duration: 4.11s
Completion tokens: 98
Result: Pass

def search(lst):
    freq_dict = {}
    for num in lst:
        if num in freq_dict:
            freq_dict[num] += 1
        else:
            freq_dict[num] = 1
    
    max_freq = 0
    max_freq_num = -1
    for num, freq in freq_dict.items():
        if freq >= num and num > max_freq_num:
            max_freq = freq
            max_freq_num = num
    
    return max_freq_num

❌ Run 9

Start time: 2023-07-18 17:16:48
Duration: 2.94s
Completion tokens: 70
Result: Fail

def search(lst):
    freq = {}
    for num in lst:
        if num in freq:
            freq[num] += 1
        else:
            freq[num] = 1
    
    for num in lst:
        if freq[num] >= num and num > 0:
            return num
    
    return -1

✅ Run 10

Start time: 2023-07-18 17:16:44
Duration: 3.6s
Completion tokens: 81
Result: Pass

def search(lst):
    freq_dict = {}
    for num in lst:
        if num in freq_dict:
            freq_dict[num] += 1
        else:
            freq_dict[num] = 1
    
    max_num = -1
    for num, freq in freq_dict.items():
        if freq >= num and num > max_num:
            max_num = num
    
    return max_num