sqrtOfx.java

class sqrtOfx {
    public int mySqrt(int x) {
        //base case 
        if(x==0 || x==1){
            return x;
        }
        int start =1;
        int end=x;
        int mid=-1;

        while(start <= end){
            mid = start +(end-start) /2;

            if((long) mid*mid>(long)x){
                end = mid-1;
            }
            else if(mid*mid ==x){
                return mid;
            }
            else{
                start=mid+1;
            }
        }
        return Math.round(end);
         
    }
}

/*
Given a non-negative integer x, return the square root of x rounded down to the nearest integer. The returned integer should be non-negative as well.

You must not use any built-in exponent function or operator.

For example, do not use pow(x, 0.5) in c++ or x ** 0.5 in python.*/