added: brute force soln for Longest Substring Without Repeating Characters

Coin Change - Leetcode 322/Coin Change - Leetcode 322.cpp

@@ -2,6 +2,30 @@
 #include <algorithm>
 using namespace std;
 
+
+/**
+ * Brute force approach with simple recursion
+ */
+class Solution {
+public:
+    int coinChange(vector<int>& coins, int amount) {
+        if (amount == 0)
+            return 0;
+        else if (amount < 0)
+            return -1;
+
+        int min_cnt = -1;
+        for (int coin : coins) {
+            int cnt = coinChange(coins, amount - coin);
+            if (cnt >= 0) 
+                min_cnt = min_cnt < 0 ? cnt + 1 : min(min_cnt, cnt + 1);
+        }
+        return min_cnt;
+    }
+};
+
+
+
 class Solution {
 public:
     int coinChange(vector<int>& coins, int amount) {

Coin Change - Leetcode 322/Coin Change - Leetcode 322.java

@@ -1,5 +1,28 @@
 import java.util.Arrays;
 
+
+/**
+ * Brute force approach with simple recursion
+ */
+class Solution {
+    public int coinChange(int[] coins, int amount) {
+        if (amount == 0)
+            return 0;
+        else if (amount < 0)
+            return -1;
+
+        int min_cnt = -1;
+        for (int coin : coins) {
+            int cnt = coinChange(coins, amount - coin);
+            if (cnt >= 0) 
+                min_cnt = min_cnt < 0 ? cnt + 1 : Math.min(min_cnt, cnt + 1);
+        }
+        return min_cnt;
+    }
+}
+
+
+
 public class Solution {
     public int coinChange(int[] coins, int amount) {
         int[] dp = new int[amount + 1];

Coin Change - Leetcode 322/Coin Change - Leetcode 322.js

@@ -1,3 +1,26 @@
+/**
+ * Brute force approach with simple recursion
+ * 
+ * @param {number[]} coins
+ * @param {number} amount
+ * @return {number}
+ */
+var coinChange = function(coins, amount) {
+    if (amount == 0)
+        return 0;
+    else if (amount < 0)
+        return -1;
+
+    let min_cnt = -1;
+    for (let coin of coins) {
+            let cnt = coinChange(coins, amount - coin);
+            if (cnt >= 0) 
+                min_cnt = min_cnt < 0 ? cnt + 1 : Math.min(min_cnt, cnt + 1);
+    }
+    return min_cnt;
+};
+
+
 /**
  * @param {number[]} coins
  * @param {number} amount

Coin Change - Leetcode 322/Coin Change - Leetcode 322.py

@@ -1,3 +1,22 @@
+class Solution:
+    def coinChange(self, coins: List[int], amount: int) -> int:
+        # Brute force with simple recursion
+        # Time: O(Coins ^ Amount)
+        # Space: O(Amount)
+        if amount == 0:
+            return 0
+        elif amount < 0:
+            return -1
+
+        min_cnt = -1
+        for coin in coins:
+            cnt = self.coinChange(coins, amount - coin)
+            if cnt >= 0:
+                min_cnt = cnt + 1 if min_cnt < 0 else min(min_cnt, cnt + 1)
+        return min_cnt
+
+
+
 class Solution:
     def coinChange(self, coins: List[int], amount: int) -> int:
         # Top Down DP (Memoization)

Longest Substring Without Repeating Characters - Leetcode 3/Longest Substring Without Repeating Characters - Leetcode 3.cpp

@@ -2,6 +2,30 @@
 #include <algorithm>
 using namespace std;
 
+
+
+class Solution {
+public:
+    int lengthOfLongestSubstring(const string s) {
+
+        int longest = 0;
+
+        for (auto i = 0; i < s.size(); ++i) {
+            for (auto substr_len = 1; i + substr_len <= s.size(); ++substr_len) {
+                unordered_set<char> seen{s.cbegin() + i, s.cbegin() + i + substr_len};
+                if (seen.size() == substr_len) 
+                    longest = max(longest, substr_len);
+            }
+        }
+
+        return longest;
+    }
+};
+// Time Complexity: O(n^3)
+// Space Complexity: O(n)
+
+
+
 class Solution {
 public:
     int lengthOfLongestSubstring(string s) {

Longest Substring Without Repeating Characters - Leetcode 3/Longest Substring Without Repeating Characters - Leetcode 3.java

@@ -1,5 +1,31 @@
 import java.util.HashSet;
 
+
+// brute force
+// Time Complexity: O(n^3)
+// Space Complexity: O(n)
+public class Solution {
+    public int lengthOfLongestSubstring(String s) {
+        int longest = 0;
+        int n = s.length();
+        for (int i = 0; i < n; i++) {
+            for (int substr_len = 1; i + substr_len <= n; ++substr_len) {
+                HashSet<Character> seen = new HashSet<>();
+                for (int j = i; j < i + substr_len; ++j) 
+                    seen.add(s.charAt(j));
+
+                if (seen.size() == substr_len)
+                    longest = Math.max(longest, substr_len);
+            }
+        }
+
+        return longest;
+    }
+}
+
+
+
+
 public class Solution {
     public int lengthOfLongestSubstring(String s) {
         HashSet<Character> set = new HashSet<>();

Longest Substring Without Repeating Characters - Leetcode 3/Longest Substring Without Repeating Characters - Leetcode 3.js

@@ -1,3 +1,26 @@
+// brute force
+// Time Complexity: O(n^3)
+// Space Complexity: O(n)
+var lengthOfLongestSubstring = function(s) {
+
+    let longest = 0;
+    let n = s.length;
+    for (let i = 0; i < n; ++i) {
+        for (let substr_len = 1; i + substr_len <= n; ++substr_len) {
+            var seen = new Set();
+            for (let j = i; j < i + substr_len; ++j) {
+                seen.add(s[j]);
+            }
+            if (seen.size == substr_len) {
+                longest = Math.max(longest, substr_len);
+            }
+        }
+    }
+
+    return longest;
+};
+
+
 var lengthOfLongestSubstring = function(s) {
     const set = new Set();
     let l = 0, longest = 0;