dict.py

animals = { 'a': ['aardvark'], 'b': ['baboon'], 'c': ['coati']}

animals['d'] = ['donkey']
animals['d'].append('dog')
animals['d'].append('dingo')

def how_many(aDict):
    '''
    aDict: A dictionary, where all the values are lists.

    returns: int, how many values are in the dictionary.
    '''
    # Your Code Here

    return sum(map(len, aDict.values()))

def how_many(aDict):
    '''
    aDict: A dictionary, where all the values are lists.

    returns: int, how many individual values are in the dictionary.
    '''
    result = 0
    for value in aDict.values():
        # Since all the values of aDict are lists, aDict.values() will 
        #  be a list of lists
        result += len(value)
    return result

def how_many(aDict):
    '''
    Another way to solve the problem.

    aDict: A dictionary, where all the values are lists.

    returns: int, how many individual values are in the dictionary.
    '''
    result = 0
    for key in aDict.keys():
        result += len(aDict[key])
    return result

def biggest(aDict):
    '''
    aDict: A dictionary, where all the values are lists.

    returns: The key with the largest number of values associated with it
    '''
    # Your Code Here
    result = {}
    for key,value in aDict.items():
        # Since all the values of aDict are lists, aDict.values() will 
        #  be a list of lists
        result[key]=len(value)
    maxCount = 0
    maxKey = ''
    for key,value in result.items():
        if value > maxCount:
            maxCount = value
            maxKey = key
    return maxKey

#alternative 

def biggest(aDict):
    '''
    aDict: A dictionary, where all the values are lists.

    returns: The key with the largest number of values associated with it
    '''
    result = None
    biggestValue = 0
    for key in aDict.keys():
        if len(aDict[key]) >= biggestValue:
            result = key
            biggestValue = len(aDict[key])
    return result