3x3 matrix lower uppper cross sum.txt

#include <stdio.h>

int main()
{
    int a[3][3]={{6,5,4},
		{1,2,5},
		{7,9,7}};
    int n=3;
    int i,j,usum=0,lsum=0;
    for(i=0;i<n;i++)
    {
        for(j=0;j<n;j++)
        {
            if(i==j)
            {
                usum+=a[i][j];
                lsum+=a[i][j];
            }
            else if(j>i)
            {
                usum+=a[i][j];
            }
            else
            {
                lsum+=a[i][j];
            }
        }
    }
    
    printf("%d",usum);
    printf("\n%d",lsum);

    return 0;
}

java:

public class Task {
 public static void main(String args[])
 {
  
 int i,j;
  int usum=0;

 int a[][]={{1,2,3},
             {4,5,6},
              {7,8,9}};
  int n=a.length;
  int lsum=0;
  for(i=0;i<n;i++)
    {
        for(j=0;j<n;j++)
        {
            if(i==j)
            {
                usum+=a[i][j];
                lsum+=a[i][j];
            }
            else if(j>i)
            {
                usum+=a[i][j];
            }
            else
            {
                lsum+=a[i][j];
            }
        }
    }
    System.out.println(usum+" "+lsum);
 }
}

python:

a=[[1,2,3],[4,5,6],[7,8,9]]

n=len(a)
usum=0
lsum=0
for i in range(len(a)):
    
        for j in range(len(a)):
        
            if i==j:
            
                usum+=a[i][j]
                lsum+=a[i][j]
           
            elif j>i:
            
                usum+=a[i][j]
            
            else:
            
                lsum+=a[i][j]
print(usum," ",lsum)