Given two binary trees, write a function to check if they are the same or not.
Two binary trees are considered the same if they are structurally identical and the nodes have the same value.
Example 1:
Input: 1 1
/ \ / \
2 3 2 3
[1,2,3], [1,2,3]
Output: true
Example 2:
Input: 1 1
/ \
2 2
[1,2], [1,null,2]
Output: false
Example 3:
Input: 1 1
/ \ / \
2 1 1 2
[1,2,1], [1,1,2]
Output: false
- 递归很容易解决
- 如果不用递归, 可以尝试层序遍历, 然后每层都有一个标记 比如说1|-2|3|.(这里-表示换行了), 反正想一个序列化的方法, 然后生成出来再对比
package leetcode100_SameTree;
import utils.TreeNode;
public class Solution {
public boolean isSameTree(TreeNode p, TreeNode q) {
if (p == null && q == null) return true;
if (p != null && q != null && p.val == q.val) {
return isSameTree(p.left, q.left) && isSameTree(p.right, q.right);
}
return false;
}
}