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“对于 str1 来说,new String( hello ) 分两步走:首先, hello 属于字符串字面量,因此编译时期会在 String Pool 中查找有没有值为 hello 的引用,如果没找到,就在字符串常量池中开辟地址空间创建一个字符串对象,指向这个 hello 字符串字面量; 然后,使用 new的方式又会在堆中创建一个字符串对象。” “对于 str3 来说,str1.intern() ...
  • Treeveer
  • Opened 
    on Sep 27, 2022
  • #12

image 关于“丢失更新”,似乎前两个隔离级别并不会解决上文所提到的逻辑上的丢失更新问题。 例如,在其他博客中所查到,“READ UNCOMMITTED 读取未提交”采用“一级封锁协议,只对修改数据的并发操作做限制”,那么是无法解决“丢失更新”问题。 由于手边没有书籍,无法找到更权威的解释,望作者解惑!!
  • YfDebug
  • Opened 
    on May 11, 2022
  • #9

68747470733a2f2f67697465652e636f6d2f7665616c39382f696d616765732f7261772f6d61737465722f696d672f32303231303131353131333831382e706e67 这个与运算的结果底下的十进制写错了吧
bug
  • feverGeek
  • 2
  • Opened 
    on Jan 29, 2022
  • #6

这是我参考总结的关键路径解法,您的关键路径部分只有说明,总觉得可以再补充点。 https://www.cnblogs.com/muziyang/p/12603884.html
  • muziyang555
  • 1
  • Opened 
    on May 10, 2020
  • #5

有向图中,如果 Vi 到 Vj 有路径,且反过来也有路径,则称这两个顶点强连通。
  • JancerWu
  • 1
  • Opened 
    on May 7, 2020
  • #4

大佬写得真好,有没有汇编程序设计的总结,复试面试有问答
  • decadeheart
  • 1
  • Opened 
    on May 7, 2020
  • #3

你写的真好,昨晚我看了好久
  • wugenqiang
  • 6
  • Opened 
    on May 3, 2020
  • #2

非常感谢大佬辛苦总结出来的计算机基础知识大全~
  • VirgilG72
  • 4
  • Opened 
    on May 2, 2020
  • #1
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