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_135_Candy.java
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package leetcode_1To300;
import java.util.Arrays;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _135_Candy {
/**
* 135. Candy
* There are N children standing in a line. Each child is assigned a rating value.
You are giving candies to these children subjected to the following requirements:
Each child must have at least one candy.
Children with a higher rating get more candies than their neighbors.
What is the minimum candies you must give?
ratings: [4, 5, 1, 1, 3, 7]
candies: [1, 1, 1, 1, 1, 1]
ratings: [4, 5, 1, 1, 3, 7]
candies: [1, 2, 1, 1, 2, 3]
ratings: [4, 5, 1, 1, 3, 7]
candies: [1, 2, 1, 1, 2, 3]
time : O(n)
space : O(n)
* @param ratings
* @return
*/
public int candy(int[] ratings) {
int[] candies = new int[ratings.length];
Arrays.fill(candies, 1);
for (int i = 1; i < candies.length; i++) {
if (ratings[i] > ratings[i - 1]) {
candies[i] = candies[i - 1] + 1;
}
}
for (int i = candies.length - 2; i >= 0; i --) {
if (ratings[i] > ratings[i + 1]) {
candies[i] = Math.max(candies[i], candies[i + 1] + 1);
}
}
int res = 0;
for (int candy : candies) {
res += candy;
}
return res;
}
}